Answer
$\textbf{(a)}\hspace{0.7cm}$See the graph
$\textbf{(b)}\hspace{0.7cm}$From the graph:
there is no $x−$intercepts, and the y−intercept is at $(0,-2)$.
$\textbf{(c)}\hspace{0.7cm} $there is no $x-$intercepts and $y−$intercept is at $(0,-2)$.
Work Step by Step
$\textbf{(a)}\hspace{0.7cm}$See the graph
$\textbf{(b)}\hspace{0.7cm}$From the graph:
there is no $x−$intercepts and the $y−$intercept is at $(0,-2)$.
$\textbf{(c)}\hspace{0.7cm}$
at $x−$intercepts $y=0$
i.e. $-\dfrac{2}{x^2+1}=0⇒2=0⇒$ Reject solution, there is no solution.
i.e there is no $x−$intercepts
at $y−$intercepts $x=0$
i.e. $y=-\dfrac{2}{0^2+1}=-2$
i.e. $ y−$intercept is $(0,-2)$
