College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.2 - Graphs of Equations in Two Variables; Circles - 1.2 Exercises - Page 102: 72

Answer

center: $(-1, -2)$ radius: $6$ units Refer to the image below for the graph.

Work Step by Step

RECALL: The circle $(x--h)^2+(y-k)^2=r^2$ has its center at $(h, k)$ and a radius of $r$ units. The given equation can be written as $(x+1)^2+(y+2)^2=6^2$, which is in the same form as the one in the recall part above. Thus, the circle has: its center at $(-1, -2)$; a radius of 6 units Plot the center. Then, plot the following points: 6 units above the center: $(-1, 4)$ 6 units below the center: $(-1, -8)$ 6 units to the left of the center: $(-7, -2)$ 6 units to the right of the center: $(5, -2)$ Connect the four points (not including the center) using a curve to form a circle.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.