Answer
x-intercept: $-1$
y-intercept: $1$
Work Step by Step
RECALL:
(1) A point where the graph touches or crosses the x-axis is called an x-intercept. Given an equation, the x-intercept/s can be found by setting $y=0$ then solving for $x$.
(2) A point where the graph touches or crosses the y-axis is called a y-intercept.
Given an equation, the y-intercept/s can be found by setting $x=0$ then solving for $y$.
Solve for the x-intercept/s by setting $y=0$ then solving for $x$:
$\begin{array}{ccc}
&y &= &\sqrt{x+1}
\\&0 &= &\sqrt{x+1}
\\&0^2 &= &(\sqrt{x+1})^2
\\&0 &= &x+1
\\&0-1 &= &x+1-1
\\&-1 &= &x
\end{array}$
The x-intercept is $-1$.
Solve for the y-intercept/s by setting $x=0$ then solving for $y$:
$\begin{array}{ccc}
&y &= &\sqrt{x+1}
\\&y &= &\sqrt{0+1}
\\&y &= &\sqrt1
\\&y &= &1
\end{array}$
The y-intercept is $1$.
