#### Answer

x-intercepts: $-\sqrt5$ and $\sqrt5$
y-intercept: $-5$

#### Work Step by Step

RECALL:
(1) A point where the graph touches or crosses the x-axis is called an x-intercept. Given an equation, the x-intercept/s can be found by setting $y=0$ then solving for $x$.
(2) A point where the graph touches or crosses the y-axis is called a y-intercept.
Given an equation, the y-intercept/s can be found by setting $x=0$ then solving for $y$.
Solve for the x-intercept/s by setting $y=0$ then solving for $x$:
$\begin{array}{ccc}
&y &= &x^2-5
\\&0 &= &x^2-5
\\&0+5 &= &x^2-5+5
\\&5 &= &x^2
\\&\pm\sqrt5 &= &x
\end{array}$
The x-intercepts are $\pm\sqrt5$.
Solve for the y-intercept/s by setting $x=0$ then solving for $y$:
$\begin{array}{ccc}
&y &= &x^2-5
\\&y &= &0^2-5
\\&y &= &-5
\end{array}$
The y-intercept is $-5$.