Answer
$\textbf{(a)}\hspace{0.5cm}$See the graph
$\textbf{(b)}\hspace{0.5cm}$From the graph:
the $x-$intercepts are at $(0,0)$ and $(0,1)$, and the $y-$intercept is at $(0,0)$.
$\textbf{(c)}\hspace{0.5cm}$ $x-$intercepts are at $(0,0)$ and $(1,0)$ and $y-$intercept is $(0,0)$
Work Step by Step
$\textbf{(a)}\hspace{0.5cm}$See the graph
$\textbf{(b)}\hspace{0.5cm}$From the graph:
the $x-$intercepts are at $(0,0)$ and $(0,1)$, and the $y-$intercept is at $(0,0)$.
$\textbf{(c)}\hspace{0.5cm}$
at $x-$intercepts $y=0$
i.e. $x^3-x^2=0\Rightarrow x^2(x-1)=0\Rightarrow x^2=0\Rightarrow x=0$ or $x-1=0\Rightarrow x=1$
i.e $x-$intercepts are at $(0,0)$ and $(1,0)$
at $y-$intercepts $x=0$
i.e. $y=0^3-0^2=0$
i.e $y-$intercept is $(0,0)$
