## College Algebra (10th Edition)

$\color{blue}{y=-5x+11}$
RECALL: (1) The slope-intercept form of a line's equation is: $y=mx+b$ where $m$ = slope and $b$ = y-intercept (2) The slope of the line that passes through the points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the formula: $m=\dfrac{y_2-y_1}{x_2-x_1}$ Solve for the slope using the formula in (2) above to obtain: $m=\dfrac{-4-1}{3-2}=\dfrac{-5}{1}=-5$ Thus, the tentative equation of the line is: $y=-5x+b$ To find the value of $b$, substitute the values of x and y of the given point $(2, 1)$ to obtain: $y=-5x+b \\1=-5(2)+b \\1=-10+b \\1+10=b \\11=b$ Thus, the equation of the line is $\color{blue}{y=-5x+11}$.