College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Review Exercises: 18

Answer

$\color{blue}{y=-\dfrac{1}{5}x-2}$

Work Step by Step

RECALL: The slope-intercept form of a line's equation is: $y=mx+b$ where $m$ = slope and $b$ = y-intercept The y-intercept of the line is $-2$. Substitute $-2$ for $b$ into the standard form to obtain the tentative equation: $y=mx+(-2) \\y=mx-2$ To find the value of $b$, substitute the values of x and y of the given point into the tentative equation above to obtain: $y=mx-2 \\-3=m(5)-2 \\-3=5m-2 \\-3+2=5m \\-1=5m \\-\frac{1}{5} = m$ Thus, the equation of the line is $\color{blue}{y=-\dfrac{1}{5}x-2}$.
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