College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Review Exercises: 12

Answer

$(x+1)^2+(y+2)^2=1$

Work Step by Step

RECALL: The standard form of a circle's equation is given as: $(x-h)^2+(y-k)^2=r^2$ where $r$ = radius and $(h, k)$ is the center. Thus, a circle with center at $(-1, -2)$ and $r=1$ has the equation: $[(x-(-1)]^2+[y-(-2)]^2=1^2 \\(x+1)^2+(y+2)^2=1$
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