#### Answer

center: $(0. 1)$
radius $=2$
x-intercepts: $-\sqrt3$ and $\sqrt3$
y-intercepts: $-1$ and $3$

#### Work Step by Step

RECALL:
The standard form of a circle's equation is given as:
$(x-h)^2+(y-k)^2=r^2$
where $r$ = radius and $(h, k)$ is the center.
The given equation can be written as:
$(x-0)^2+(y-1)^2=2^2$
Thus, the given circle has:
center: $(0, 1)$
radius = $2$
To graph the circle, perform the following steps:
(1) Plot the center $(0, 1)$.
(2) With a radius of 2 units, plot the following points:
2 units above the center: $(0, 3)$
2 units below the center: $(0, -1)$
2 units to the left of the center: $(-2, 1)$
2 units to the right of the center: $(2, 1)$
(3) Connect the four point in step (2) (not including the center) using a smooth curve to form a circle.
(refer to the attached image in the answer part above for the graph)
The circle has the following y-intercepts: $3$ and $-1$.
To find the x-intercept, set $y=0$ then solve for $x$ to obtain:
$x^2 + (y-1)^2=4
\\x^2 + (0-1)^2=4
\\x^2+1=4
\\x^2=4-1
\\x^2=3
\\x = \pm\sqrt{3}$
Thus, the x-intercepts are $\sqrt3$ and $-\sqrt3$.