Answer
{$x|0\leq x\leq\frac{4}{3}$}
Work Step by Step
We simplify as follows:
$2+|2-3x|\leq4$
$|2-3x|\leq2$
$-2\leq2-3x\leq2$
$-4\leq-3x\leq0$
$-\frac{4}{3}\leq-x\leq0$
$0\leq x\leq\frac{4}{3}$
{$x|0\leq x\leq\frac{4}{3}$}
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