Answer
$x=-3$ or $x=2$
Work Step by Step
We solve by factoring:
$x(1+x)=6$
$x+x^{2}=6$
$x^{2}+x-6=0$
$(x+3)(x-2)=0$
$(x+3)=0$ or $(x-2)=0$
$x=-3$ or $x=2$
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