College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Review Exercises: 12

Answer

$x=2$

Work Step by Step

We solve: $\sqrt{1+x^{3}}=3$ $(\sqrt{1+x^{3}})^2=3^2$ $1+x^{3}=9$ $x^{3}=9-1$ $x^{3}=8$ $x=\sqrt[3]{8}$ $x=2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.