College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Review Exercises: 14

Answer

$x=\pm 2$ or $x=\pm 1$

Work Step by Step

We solve: $x^{4}-5x^{2}+4=0$ $(x^{2}-4)(x^{2}-1)=0$ $x^{2}-4=0$ or $x^{2}-1=0$ $x=\pm \sqrt{4}$ or $x=\pm \sqrt{1}$ $x=\pm 2$ or $x=\pm 1$
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