Answer
$x=\pm 3$
Work Step by Step
We solve:
$\sqrt[3]{x^{2}-1}=2$
$(\sqrt[3]{x^{2}-1})^{3}=2^3$
$x^{2}-1=8$
$x^{2}=8+1$
$x^{2}=9$
$x=\pm \sqrt{9}$
$x=\pm 3$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 1 - Review Exercises - Page 145: 11
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