Answer
{$x|x\lt-1$ or $x\gt\frac{7}{3}$}
Work Step by Step
We simplify as follows:
$1-|2-3x|\lt-4$
$-|2-3x|\lt-5$
$|2-3x|\gt5$
$2-3x\lt-5$ or $2-3x\gt5$
$-3x\lt-7$ or $-3x\gt3$
$-x\lt-\frac{7}{3}$ or $-x\gt1$
$x\gt\frac{7}{3}$ or $x\lt-1$
{$x|x\lt-1$ or $x\gt\frac{7}{3}$}