Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Exercise Set: 44

Answer

The solutions are $\frac{-9}{2}$ and $\frac{9}{2}$.

Work Step by Step

4$y^{2}$-81=0 $(2y)^{2}$-$9^{2}$=0 (2y+9)(2y-9)=0 2y+9 =0 or 2y-9=0 2y+9-9 =0 -9 or 2y-9+9=0+9 2y=-9 or 2y=9 $\frac{2y}{2}$=$\frac{-9}{2}$ or $\frac{2y}{2}$=$\frac{9}{2}$ y=$\frac{-9}{2}$ or y= $\frac{9}{2}$ The solutions are $\frac{-9}{2}$ and $\frac{9}{2}$. Check Let x= $\frac{-9}{2}$ 4$y^{2}$-81=0 4$(-9/2)^{2}$-81=0 4*$\frac{81}{4}$-$\frac{324}{4}$=0 $\frac{324}{4}$-$\frac{324}{4}$=0 0=0 Let x= $\frac{9}{2}$ 4$y^{2}$-81=0 4$(9/2)^{2}$-81=0 4*$\frac{81}{4}$-$\frac{324}{4}$=0 $\frac{324}{4}$-$\frac{324}{4}$=0 0=0
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