Answer
$y=0$ or $y=\frac{3}{2}$
Work Step by Step
We simplify as follows:
$12y=8y^{2}$
$8y^{2}-12y=0$
$4y(2y-3)=0$
$4y=0$ or $2y-3=0$
$y=0$ or $2y=3$
$y=0$ or $y=\frac{3}{2}$
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