Answer
The solutions are -2 and 9.
Work Step by Step
(y-5)(y-2)=28
$y^{2}$-2y-5y+10=28
$y^{2}$-7y+10-28=28-28
$y^{2}$-7y+10-28=0
$y^{2}$-7y-18=0
$y^{2}$+2y-9y-18=0
y(y+2)-9(y+2)=0
(y-9)(y+2)=0
y-9=0 or y+2=0
y=9 or y=-2
The solutions are -2 and 9.
Check
Let x=-2
(y-5)(y-2)=28
(-2-5)(-2-2)=28
-7(-4)=28
28=28
Let x=9
(y-5)(y-2)=28
(9-5)(9-2)=28
4*7=28
28=28
