Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Exercise Set: 47

Answer

The solutions are -5 and 3.

Work Step by Step

$x^{2}$+2x-15=0 $x^{2}$+5x-3x-15=0 x(x+5)-3(x+5)=0 (x-3)(x+5)=0 x-3=0 or x+5=0 x-3+3=0+3 or x+5-5=0-5 x=3 or x=-5 The solutions are -5 and 3. Chec Let x=-5 $(-5)^{2}$+2(-5)-15=0 25-10-15=0 0=0 Let x=3 $x^{2}$+2x-15=0 $3^{2}$+2*3-15=0 9+6-15=0 0=0
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