Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Exercise Set - Page 458: 67

Answer

$x=\frac{6}{7}$ or $x=1$

Work Step by Step

We simplify as follows: $3x^{2}-20x=-4x^{2}-7x-6$ $7x^{2}-13x+6=0$ $(7x-6)(x-1)=0$ $7x-6=0$ or $x-1=0$ $7x=6$ or $x=1$ $x=\frac{6}{7}$ or $x=1$
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