Answer
$x^2y^3*(y^2+1)(y^4-y^2+1)$
Work Step by Step
$x^2y^9+x^2y^3$
$x^2(y^9+y^3)$
$y^9+y^3$
$(y^3)^3+(y^1)^3$
$(y^3+y)((y^3)^2-y^3*y+(y^1)^2)$
$(y^3+y)(y^6-y^4+y^2)$
$x^2(y^9+y^3)$
$x^2(y^3+y)(y^6-y^4+y^2)$
$x^2*(y^2*y+y)(y^6-y^4+y^2)$
$x^2*(y(y^2+1))(y^6-y^4+y^2)$
$x^2y*(y^2+1)(y^6-y^4+y^2)$
$x^2y*(y^2+1)*(y^6-y^4+y^2)$
$x^2y*(y^2+1)*((y^2)^3-(y^2)^2+y^2)$
$x^2y*(y^2+1)*y^2((y^2)^2-(y^2)+1)$
$x^2y*y^2*(y^2+1)*((y^2)^2-(y^2)+1)$
$x^2y^3*(y^2+1)(y^4-y^2+1)$
