Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.5 - Factoring by Special Products - Exercise Set: 59

Answer

(z-1)($z^{2}$+z+$1^{2}$)

Work Step by Step

$z^{3}$-1=$z^{3}$-$1^{3}$=(z-1)($z^{2}$+z1+$1^{2}$) (z-1)($z^{2}$+z+$1^{2}$)
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