Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.5 - Factoring by Special Products - Exercise Set - Page 448: 92

Answer

(m+3)(m-3)(n+8)

Work Step by Step

$m^{2}$(n+8)-9(n+8)=($m^{2}$-9)(n+8)=($m^{2}$-$3^{2}$)(n+8)= (m+3)(m-3)(n+8)
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