Answer
(5y-2x)(25$y^{2}$ +10xy+4$x^{2}$)
Work Step by Step
125$y^{3}$-8$x^{3}$=$(5y)^{3}$ -$(2x)^{3}$=
(5y-2x)($(5y)^{2}$ +(5y)(2x)+$(2x)^{2}$)=
(5y-2x)(25$y^{2}$ +10xy+4$x^{2}$)
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