Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.5 - Factoring by Special Products - Exercise Set - Page 448: 70

Answer

$ (x-y^2)(x^2 +xy^2 + y^4) $

Work Step by Step

$x^3 - y^6 = x^3 - (y^2)^3 =(x-y^2)(x^2 +xy^2 + (y^2)^2) = (x-y^2)(x^2 +xy^2 + y^4) $
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