Answer
(-infinity, $3)$
Work Step by Step
$(x+2)/(x-3) < 1$
Denominator is zero when $x=3$
$(x+2)/(x-3) < 1$
$(x+2)/(x-3) = 1$
$(x+2)*(x-3)/(x-3) = 1*(x-3)$
$x+2 = x-3$
$x+5=x$
$5=0$ (false)
(-infinity, $3)$
$(3$, infinity)
Let $x=0$, $x=10$
$x=0$
$(x+2)/(x-3) < 1$
$(0+2)/(0-3) < 1$
$2/-3 < 1$
$-2/3 < 1$ (true)
$x=10$
$(x+2)/(x-3) < 1$
$(10+2)/(10-3) < 1$
$12/7 < 1$ (false)