Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.4 - Nonlinear Inequalities in One Variable - Exercise Set - Page 798: 20

Answer

$[-1, 4)$

Work Step by Step

$(x+1)/(x-4)\leq0$ Numerator is zero when $x=-1$ Denominator is zero when $x=4$ (-infinity, $-1]$ $[-1, 4)$ $(4$, infinity) Let $x=-10$, $x=0$, $x=10$ $x=-10$ $(x+1)/(x-4)\leq0$ $(-10+1)/(-10-4)\leq0$ $(-11)/(-14)\leq0$ $11/14 \leq 0$ (false) $x=0$ $(x+1)/(x-4)\leq0$ $(0+1)/(0-4)\leq0$ $1/-4 \leq 0$ $-1/4 \leq 0$ (true) $x=10$ $(x+1)/(x-4)\leq0$ $(10+1)/(10-4)\leq0$ $11/6 \leq 0$ (false)
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