Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.4 - Nonlinear Inequalities in One Variable - Exercise Set: 10

Answer

$(-\infty,2] \cup [4, 6]$

Work Step by Step

$(x-6)(x-4)(x-2)\leq$ Write as an equation. $(x-6)(x-4)(x-2)=0$ Solve as an equation. $x=6$ $x=4$ $x=2$ Plot these numbers on a number line,split them into intervals, take one test point from each interval, and check them to see if they are true. If they are true, then it is a solution. In this case, it is $(-\infty,2] \cup [4, 6]$
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