Chapter 11 - Section 11.4 - Nonlinear Inequalities in One Variable - Exercise Set - Page 798: 17

$(-1$, infinity)

$5/(x+1) > 0$ Denominator is zero when $x=-1$ $5/(x+1) > 0$ $5*(x+1)/(x+1) > 0*(x+1)$ $5>0$ (true) (-infinity, $-1)$ $(-1$, infinity) Let $x=-10$, $x=0$ $x=-10$ $5/(x+1) > 0$ $5/(-10+1) > 0$ $5/(-9) > 0$ $-5/9 > 0$ (false) $x=0$ $5/(x+1) > 0$ $5/(0+1) > 0$ $5/1 > 0$ $5>0$ (true)