Answer
$\dfrac{\sqrt{3x^{5}}}{6}=\dfrac{x^{3}}{2\sqrt{3x}}$
Work Step by Step
$\dfrac{\sqrt{3x^{5}}}{6}$
First, simplify this expression:
$\dfrac{\sqrt{3x^{5}}}{6}=\dfrac{x^{2}\sqrt{3x}}{6}=...$
Multiply this expression by $\dfrac{\sqrt{3x}}{\sqrt{3x}}$ and simplify again if possible:
$...=\dfrac{x^{2}\sqrt{3x}}{6}\cdot\dfrac{\sqrt{3x}}{\sqrt{3x}}=\dfrac{x^{2}\sqrt{(3x)^{2}}}{6\sqrt{3x}}=\dfrac{x^{2}(3x)}{6\sqrt{3x}}=\dfrac{3x^{3}}{6\sqrt{3x}}=\dfrac{x^{3}}{2\sqrt{3x}}$
