Answer
$\dfrac{\sqrt[3]{3x^{5}}}{10}=\dfrac{3x^{2}}{10\sqrt[3]{9x}}$
Work Step by Step
$\dfrac{\sqrt[3]{3x^{5}}}{10}$
First, simplify this expression:
$\dfrac{\sqrt[3]{3x^{5}}}{10}=\dfrac{x\sqrt[3]{3x^{2}}}{10}=...$
Multiply this fraction by $\dfrac{\sqrt[3]{9x}}{\sqrt[3]{9x}}$ and simplify again if possible:
$...=\dfrac{x\sqrt[3]{3x^{2}}}{10}\cdot\dfrac{\sqrt[3]{9x}}{\sqrt[3]{9x}}=\dfrac{x\sqrt[3]{27x^{3}}}{10\sqrt[3]{9x}}=\dfrac{x(3x)}{10\sqrt[3]{9x}}=\dfrac{3x^{2}}{10\sqrt[3]{9x}}$
