Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.5 - Rationalizing Numerators and Denominators of Radical Expressions - Exercise Set: 46

Answer

$\sqrt{\dfrac{3}{2}}=\dfrac{3}{\sqrt{6}}$

Work Step by Step

$\sqrt{\dfrac{3}{2}}$ Rewrite this expression as $\dfrac{\sqrt{3}}{\sqrt{2}}$: $\sqrt{\dfrac{3}{2}}=\dfrac{\sqrt{3}}{\sqrt{2}}=...$ Multiply this expression by $\dfrac{\sqrt{3}}{\sqrt{3}}$ and simplify if possible: $...=\dfrac{\sqrt{3}}{\sqrt{2}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{\sqrt{3^{2}}}{\sqrt{6}}=\dfrac{3}{\sqrt{6}}$
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