Answer
$\sqrt[3]{\dfrac{7}{8}}=\dfrac{7}{2\sqrt[3]{49}}$
Work Step by Step
$\sqrt[3]{\dfrac{7}{8}}$
Rewrite this expression as $\dfrac{\sqrt[3]{7}}{\sqrt[3]{8}}$ and simplify it:
$\sqrt[3]{\dfrac{7}{8}}=\dfrac{\sqrt[3]{7}}{\sqrt[3]{8}}=\dfrac{\sqrt[3]{7}}{2}=...$
Multiply this fraction by $\dfrac{\sqrt[3]{49}}{\sqrt[3]{49}}$ and simplify again if possible:
$...=\dfrac{\sqrt[3]{7}}{2}\cdot\dfrac{\sqrt[3]{49}}{\sqrt[3]{49}}=\dfrac{\sqrt[3]{343}}{2\sqrt[3]{49}}=\dfrac{7}{2\sqrt[3]{49}}$