Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.5 - Rationalizing Numerators and Denominators of Radical Expressions - Exercise Set - Page 718: 55

Answer

$\dfrac{\sqrt{2x}}{11}=\dfrac{2x}{11\sqrt{2x}}$

Work Step by Step

$\dfrac{\sqrt{2x}}{11}$ Multiply this expression by $\dfrac{\sqrt{2x}}{\sqrt{2x}}$ and simplify if possible: $\dfrac{\sqrt{2x}}{11}=\dfrac{\sqrt{2x}}{11}\cdot\dfrac{\sqrt{2x}}{\sqrt{2x}}=\dfrac{\sqrt{(2x)^{2}}}{11\sqrt{2x}}=\dfrac{2x}{11\sqrt{2x}}$
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