Answer
The initial horizontal component of momentum is $83.9~kg~m/s$.
The initial vertical component of momentum is $70.4~kg~m/s$.
Work Step by Step
$P_x = mv_{0x} = mv_0~\cos(\theta)$
$P_x = (7.30~kg)(15.0~m/s)~\cos(40.0^{\circ})$
$P_x = 83.9~kg~m/s$
$P_y = mv_{0y} = mv_0~\sin(\theta)$
$P_y = (7.30~kg)(15.0~m/s)~\sin(40.0^{\circ})$
$P_y = 70.4~kg~m/s$
The initial horizontal component of momentum is $83.9~kg~m/s$.
The initial vertical component of momentum is $70.4~kg~m/s$.
