University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 8 - Momentum, Impulse, and Collision - Problems - Exercises - Page 263: 8.1

Answer

(a) $P = 1.20\times 10^5~kg~m/s$ (b) (i) $v = 60.0~m/s$ (ii) $v = 26.8~m/s$

Work Step by Step

(a) $P = mv = (10,000~kg)(12.0~m/s)$ $P = 1.20\times 10^5~kg~m/s$ (b) (i) $mv = P$ $v = \frac{P}{m} = \frac{1.20\times 10^5~kg~m/s}{2000~kg}$ $v = 60.0~m/s$ (ii) We can find the kinetic energy of the truck. $\frac{1}{2}mv^2 = \frac{1}{2}(10,000~kg)(12.0~m/s)^2$ $K = 7.20\times 10^5~J$ We can find the speed of the SUV. $\frac{1}{2}mv^2 = K$ $v^2 = \frac{2K}{m}$ $v = \sqrt{\frac{2K}{m}}$ $v = \sqrt{\frac{(2)(7.20\times 10^5~J)}{2000~kg}}$ $v = 26.8~m/s$
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