University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 6 - Work and Kinetic Energy - Problems - Discussion Questions - Page 194: Q6.10

Answer

The change in speed from 15 m/s to 20 m/s results in a greater change in kinetic energy.

Work Step by Step

We know that $K=\frac{1}{2}mv^2$. A change in speed from 10 m/s to 15 m/s results in $\Delta K=\frac{1}{2}m(15^2-10^2) = 62.5m$. A change in speed from 15 m/s to 20 m/s results in $\Delta K=\frac{1}{2}m(20^2-15^2) = 87.5m$.
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