Answer
$a = 6.61~m/s^2$
Work Step by Step
We can find the tension $T$ in the rope.
$T~sin(\theta) = mg$
$T = \frac{mg}{sin(\theta)}$
We can use a force equation to find the acceleration.
$T~cos(\theta) = ma$
$mg~cot(\theta) = ma$
$a = g~cot(\theta) = (9.80~m/s^2)~cot(56.0^{\circ})$
$a = 6.61~m/s^2$
