University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 44 - Particle Physics and Cosmology - Problems - Exercises - Page 1519: 44.11

Answer

a). 30.6 GeV, b). 8.0 GeV.

Work Step by Step

a). Mass of alpha particle can be calculated by subtracting 2 electron masses from the $He_{2}^{4}$ atomic mass :- $=4.001506u$. Then $mc^{2}=(4.001506u)\times(931.5MeV/u)=3.727GeV.$ Now, masses of target and projectile particles are equal, so $E_{a}^{2}=2mc^{2}(E_{m}+mc^{2})$ $Since, E_{a}^{2}=16 GeV, E_{m}=30.6 \,GeV$, b). Each beam must have $\frac{1}{2}E_{a}=8.0\,GeV.$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.