University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 43 - Nuclear Physics - Problems - Discussion Questions - Page 1474: Q43.7

Answer

See explanation.

Work Step by Step

The $\alpha$ particle is bound more tightly to the nucleus than a nucleon, i.e., it has more binding energy. Energetically, it’s more favorable to emit an $\alpha$ than a single nucleon. Furthermore, the $\alpha$ particle has no spin, but nucleons have spin 1/2. The nucleus can emit an $\alpha$ without changing its angular momentum, which facilitates the decay.
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