University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 42 - Molecules and Condensed Matter - Problems - Exercises - Page 1436: 42.29

Answer

See explanation.

Work Step by Step

a, i. First evaluate $\frac{eV}{kT}$ for the given voltage and temperature. $\frac{(1.6\times10^{-19}C)(0.00100V)}{(1.381\times10^{-23}J/K)(290K)}=0.0400$ Now find the current at this temperature using equation 42.22 and the given saturation current. $I=(0.500mA)(e^{eV/kT}-1)=0.0204 mA$ ii. Repeat the calculation using this voltage, to find a current of -0.0196 mA. iii. Repeat the calculation using this voltage, to find a current of 26.8 mA. iv. Repeat the calculation using this voltage, to find a current of -0.491 mA. b. For very small voltages, the current and voltage are approximately proportional.
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