University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 42 - Molecules and Condensed Matter - Problems - Exercises - Page 1436: 42.28


See explanation.

Work Step by Step

a. The energy requirement matches the energy of the maximum-wavelength photon. $$E= hf=h\frac{c}{\lambda} $$ $$\lambda =\frac{hc}{E}=\frac{1.24\times10^{-6}eV\cdot m}{0.67eV}=1.85\times10^{-6}m$$ b. $$E= hf=h\frac{c}{\lambda} $$ $$\lambda =\frac{hc}{E}=\frac{1.24\times10^{-6}eV\cdot m}{1.12eV}=1.11\times10^{-6}m $$
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