University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 41 - Quantum Mechanics II: Atomic Structure - Problems - Exercises - Page 1402: 41.22

Answer

See explanation.

Work Step by Step

a. This is done in example 41.6, at the top of page 1382. The energy is of this state is lowered. $$U=-(9.285\times10^{-24}J/T)(1.60T)=-1.486\times10^{-23}J$$ $$=-9.29\times10^{-5}eV$$ b. Since n=1, $l=0$. In the 1s state there is no orbital magnetic dipole interaction. For larger values of n, there can be nonzero values of $l$, and yes, then there could be an orbital magnetic dipole interaction.
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