University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 41 - Quantum Mechanics II: Atomic Structure - Problems - Exercises - Page 1402: 41.21

Answer

See explanation.

Work Step by Step

The interaction energy between an external magnetic field and the orbital angular momentum is given by $U=m_l\mu_B B$. a. The 5g level is split into 9 levels by the magnetic field. For the 5g level, $l=4$ and there are $2l+1 = 9$ different $m_l$ values/states. b. Each $m_l$ level is shifted in energy an amount given by $U=m_l\mu_B B$, so adjacent levels differ in energy by $\Delta U= \mu_B B$. $$\Delta U =(5.79\times10^{-5}eV/T)(0.600T)= 3.47\times10^{-5}eV $$ c. There are 9 equally-spaced levels, and we just calculated the energy separation between adjacent levels. The separation between the highest energy ($m_l=4$) and the lowest energy ($m_l=-4$) is $\Delta U= 8 \mu_B B$. $$\Delta U =8(5.79\times10^{-5}eV/T)(0.600T)= 2.78\times10^{-4}eV $$
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