University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 40 - Quantum Mechanics I: Wave Functions - Problems - Exercises - Page 1354: 40.14

Answer

77.5 nm.

Work Step by Step

The energy levels in a 1D box are given by the equation $E_n=\frac{n^2 h^2}{8mL^2}$. The ground state has n=1, and the second excited level has n = 3. $\Delta E = E_3-E_1=\frac{3^2 h^2}{8mL^2}-\frac{1^2 h^2}{8mL^2}=8E_1$ We are told that this energy difference is $ 8E_1=16.0 eV $. Solve for the wavelength. $$\lambda =\frac{hc}{\Delta E}=\frac{1.24\times10^{-6}eV\cdot m}{16.0eV}=7.75\times10^{-8}m$$
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