Answer
(a) Since the boxes are tied together, the acceleration of the 4.00-kg crate is also $2.50~m/s^2$.
(b) $F_T = 10.0~N$
(c) The net force is directed to the right in the direction of the pull $F$. In this situation, $F$ has a larger magnitude than $T$.
(d) F = 25.0 N
Work Step by Step
(a) Since the boxes are tied together, the acceleration of the 4.00-kg crate is also $2.50~m/s^2$.
(b) $F_T = ma = (4.00~kg)(2.50~m/s^2)$
$F_T = 10.0~N$
(c) The net force is directed to the right in the direction of the pull $F$. In this situation, $F$ has a larger magnitude than $T$.
(d) $\sum F_x = ma$
$F - F_T = ma$
$F = ma + F_T$
$F = (6.00~kg)(2.50~m/s^2) + (10.0~N)$
$F = 25.0~N$
