## University Physics with Modern Physics (14th Edition)

We can find the acceleration due to gravity on Planet X. $y = \frac{1}{2}at^2$ $a = \frac{2y}{t^2} = \frac{(2)(10.0~m)}{(3.40~s)^2}$ $a = 1.73~m/s^2$ Note that the acceleration for the freely falling object is the acceleration due to gravity $g_x$ on Planet X. $weight = mg_x = (0.100~kg)(1.73~m/s^2)$ $weight = 0.173~N$ The weight of the golf ball on Planet X is 0.173 N.