Answer
$1.01\times10^{-32}J$.
Work Step by Step
The Heisenberg uncertainty principle limits our knowledge.
$$\Delta E \Delta t \geq \frac{\hbar}{2}$$
Find the minimum uncertainty in energy.
$$\Delta E = \frac{\hbar}{2\;\Delta t}$$
$$\Delta E = 1.01\times10^{-32}J=6.34\times10^{-14}eV$$
The uncertainty in the energy is a tiny fraction of a typical atomic state energy.
