Answer
$3.90\times10^{-34}m$.
Work Step by Step
$\lambda=\frac{h}{p}=\frac{h}{mv}$
$\lambda=\frac{6.626\times10^{-34}J \cdot s}{(5.00\times10^{-3}kg)(340\;m/s)}= 3.90\times10^{-34}m $
This is unimaginably tiny, and the bullet will not exhibit wavelike properties.
