Answer
The atom with an electron at high n. The electron at low n.
Work Step by Step
The total energy of the atom is given by equation 39.15, $E_n=-\frac{hcR}{n^2}$. The atom with the electron at high n has the greater energy. It is important to note the minus sign; the total energy is negative in each case, but the high-n atom’s energy is not as negative.
The orbital speed of electrons in the Bohr model is given by equation 39.9, $v_n=\frac{1}{\epsilon_o}\frac{e^2}{2nh}$. The atom with the electron at low n has the greater speed.
There is no contradiction because an atom’s total energy is both kinetic and potential. The lower-n electron is moving faster, and has more kinetic energy (which is always positive). However, being closer to the nucleus, it has a more negative potential energy, and so the atom’s total energy ends up being more negative than that of the high-n atom.